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NEET NEET SOLVED PAPER 2013

  • question_answer
    A uniform force of \[(3\mathbf{i}+\mathbf{j})\] N acts on a particle of mass 2 kg. Hence the particle is displaced from position \[(2\mathbf{i}+\mathbf{k})\] m to position \[(4\mathbf{i}+3\mathbf{j}-\mathbf{k})\] m. The work done by the force on the particle is

    A)  9 J             

    B)  6 J

    C)  13 J            

    D)  15 J

    Correct Answer: A

    Solution :

     Given, force F = 3 i + j \[{{r}_{1}}=(2i+k)m\]and\[{{r}_{2}}=(4i+3J-k)m\] \[\therefore \]\[s={{r}_{2}}-{{r}_{1}}=(4i+3j-k)-(2i+k)\] \[=(2i+3j-2k)m\] \[\therefore \]\[W=F\cdot s=(3i+j)\cdot (2i+3j-2k)\] \[\begin{align}   & =3\times 2+3+0 \\  & =6+3=9\,J \\ \end{align}\]


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