A) \[X=\overline{\overline{A}}\cdot \overline{\overline{B}}\]
B) \[X=\overline{A\cdot B}\]
C) \[X=A\cdot B\]
D) \[X=\overline{A+B}\]
Correct Answer: C
Solution :
\[X=\overline{\overline{AB}}=A\cdot B\](i.e., AND gate) If the output X of NAND gate is connected to the input of NOT gate (made from NAND gate by joining two inputs) from the given figure then we get back an AND gate.You need to login to perform this action.
You will be redirected in
3 sec