A) 0.65 eV
B) 1.0 eV
C) 1.3 eV
D) 1.5 eV
Correct Answer: B
Solution :
For photo electric equation \[{{(KE)}_{\max }}=hv-{{\phi }_{0}}\] For the first condition \[0.5=E-{{\phi }_{0}}\] ?(i) For the second condition \[0.8-1.2E-{{\phi }_{0}}\] ?(ii) From Eqs. (i) and (ii) \[0.5=E-{{\phi }_{0}}\] and \[0.8=1.2E-{{\phi }_{0}}\] \[-0.3=-0.2E\] \[E=\frac{0.3}{0.2}1.5eV\] From expression (i) \[0.5=1.5-{{\phi }_{0}}\Rightarrow {{\phi }_{0}}=0.5-0.5=1eV\]
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