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NEET NEET SOLVED PAPER 2014

  • question_answer
    The binding energy per nucleon of \[_{3}^{7}Li\] and \[_{2}^{4}He\] nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction \[_{3}^{7}Li+_{1}^{1}H\to _{2}^{4}He+_{2}^{4}He+Q\], the value of energy Q released is [AIPMT 2014]

    A)  19.6 MeV        

    B)  -2.4 MeV

    C)  8.4 MeV          

    D)  17.3 MeV

    Correct Answer: D

    Solution :

    The binding energy for\[{{\,}_{1}}{{\text{H}}^{\text{1}}}\] is around zero and also not given in the question so we can ignore it \[Q=24(4\times 7.06)-7\times (5.60)\]       \[=(8\times 7.06)-(7\times 5.60)\]       \[=(56.48-39.2)MeV\] \[=17.28\text{MeV}\simeq \text{17}\text{.3MeV}\]


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