NEET NEET SOLVED PAPER 2014

  • question_answer
    Calculate the energy in joule corresponding to light of wavelength 45 nm : (Planck's constant \[h=6.63\times {{10}^{-34}}\] Js;   speed   of light \[c=3\times {{10}^{8}}m{{s}^{-1}})\] [AIPMT 2014]

    A)  \[6.67\times {{10}^{15}}\]       

    B)  \[6.67\times {{10}^{11}}\]

    C)  \[4.42\times {{10}^{-15}}\]       

    D)  \[4.42\times {{10}^{-18}}\]

    Correct Answer: D

    Solution :

    The wavelength of light is related to its energy by the equation, \[E=\frac{hc}{\lambda }.\] Given, \[\lambda =45nm=45\times {{10}^{-9}}m\] \[[\because \,1nm={{10}^{-9}}m]\] Hence, \[E=\frac{6.63\times {{10}^{-34}}js\times 3\times {{10}^{8}}m{{s}^{-1}}}{45\times {{10}^{-9}}m}\] \[=4.42\times {{10}^{-18}}\text{J}\] Hence, the energy corresponds to light of wavelength 45 nm is \[4.42\times {{10}^{-18}}J.\]


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