A) 3.5
B) 5.9
C) 16.3
D) 110.8
Correct Answer: A
Solution :
If the trajectory is same for both the projectiles, their maximum height will be same. \[{{({{H}_{\max }})}_{1}}={{({{H}_{\max }})}_{2}}\] \[\frac{u_{1}^{2}{{\sin }^{2}}\theta }{2{{g}_{1}}}=\frac{u_{2}^{2}{{\sin }^{2}}\theta }{2{{g}_{2}}}\] \[\frac{u_{1}^{2}}{u_{2}^{2}}=\frac{{{g}_{1}}}{{{g}_{2}}}\Rightarrow \frac{{{(5)}^{2}}}{{{(3)}^{2}}}=\frac{9.8}{{{g}_{2}}}\] \[{{g}_{2}}=\frac{9.8\times 9}{25}=3.5m/{{s}^{2}}\]You need to login to perform this action.
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