A) 25N
B) 50N
C) 78.5N
D) 157N
Correct Answer: D
Solution :
\[\Rightarrow \,\,\,m=50kg\Rightarrow r=0.5\Rightarrow \alpha =2rev/{{s}^{2}}\] Torque produce by the tension in the string \[=T\times R=T\times 0.5=\frac{T}{2}Nm\,\,\,\,......(i)\] We know \[\tau =/\alpha \,\,\,\,\,\,\,\,\,\,.......(ii)\] From Eqs. (i) and (ii), \[=\left( \frac{M{{R}^{2}}}{2} \right)\times (2\times 2\pi )\frac{rad}{{{s}^{2}}}\] \[\therefore \] \[{{l}_{solid}}{{\,}_{cylinder}}=\frac{M{{R}^{2}}}{2}\] \[\frac{T}{2}=\frac{50\times {{(0.5)}^{2}}}{2}\times 4\pi \] \[T=50\times \frac{1}{4}\times 4\pi \] \[=50\pi =157N\]You need to login to perform this action.
You will be redirected in
3 sec