NEET NEET SOLVED PAPER 2014

  • question_answer
                        Among the following complexes, the one which shows zero crystal field stabilisation energy (CFSE) is [AIPMT 2014]

    A)  \[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{3+}}\]     

    B)  \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{3+}}\]

    C)  \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{2+}},\]   

    D)   \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]

    Correct Answer: B

    Solution :

    The CFSE for octahedral complex is given by \[CFSE=[-0.4{{t}_{2g}}{{e}^{-}}+0.6{{e}_{g}}{{e}^{-}}]\] For \[M{{n}^{3+}},\,[3{{d}^{4}}]\to \,t_{2g}^{3}\,e_{g}^{1}\] \[\therefore \]      \[CFSE=[-0.4\,\times 3+0.6\times 1]\]  = 0.6 For \[F{{e}^{3+}},[3{{d}^{5}}]\to t_{2g}^{3}e_{g}^{2}\] \[CFSE\,=[-(0.4\times 3)+(0.6\times 2)]=0\] For \[C{{o}^{2+}},[3{{d}^{7}}]\to t_{2g}^{5}e_{g}^{2}\] \[CFSE\,=[(-0.4\times 5)\,+(2\times 0.6)]\,=-0.8\] For \[C{{o}^{3+}},[3{{d}^{6}}]\to t_{2g}^{4}e_{g}^{2}\] \[CFSE=[(-0.4\times 4)\,+(2\times 0.6)]=-0.4\]


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