(I) \[{{H}_{2}}{{O}_{2}}\,+{{O}_{3}}\,\xrightarrow{\,}\,{{H}_{2}}O\,+2{{O}_{2}}\] [AIPMT 2014] |
(II) \[{{H}_{2}}{{O}_{2}}+A{{g}_{2}}O\to 2Ag+{{H}_{2}}O+{{O}_{2}}\] |
A) oxidising in (I) and reducing in (II)
B) reducing in (I) and oxidizing in (II)
C) reducing in (I) and (II)
D) oxidising in (I) and (II)
Correct Answer: A
Solution :
In the reaction, Since \[{{H}_{2}}{{O}_{2}}\] oxidises, \[{{O}_{3}}\] into\[{{O}_{2}}\], thus it behaves as an oxidising agent. Further, in the reaction, Here \[{{H}_{2}}{{O}_{2}}\] reduces \[A{{g}_{2}}O\] into metallic silver [Ag] (as oxidation number is reducing from +1 to 0). Thus, \[{{H}_{2}}{{O}_{2}}\] behaves as a reducing agent.You need to login to perform this action.
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