A) \[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
B) \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
C) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{2+}},\]
D) \[{{[Co{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
Correct Answer: B
Solution :
The CFSE for octahedral complex is given by \[CFSE=[-0.4{{t}_{2g}}{{e}^{-}}+0.6{{e}_{g}}{{e}^{-}}]\] For \[M{{n}^{3+}},\,[3{{d}^{4}}]\to \,t_{2g}^{3}\,e_{g}^{1}\] \[\therefore \] \[CFSE=[-0.4\,\times 3+0.6\times 1]\] = 0.6 For \[F{{e}^{3+}},[3{{d}^{5}}]\to t_{2g}^{3}e_{g}^{2}\] \[CFSE\,=[-(0.4\times 3)+(0.6\times 2)]=0\] For \[C{{o}^{2+}},[3{{d}^{7}}]\to t_{2g}^{5}e_{g}^{2}\] \[CFSE\,=[(-0.4\times 5)\,+(2\times 0.6)]\,=-0.8\] For \[C{{o}^{3+}},[3{{d}^{6}}]\to t_{2g}^{4}e_{g}^{2}\] \[CFSE=[(-0.4\times 4)\,+(2\times 0.6)]=-0.4\]You need to login to perform this action.
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