A) \[C{{H}_{3}}-{{(C{{H}_{2}})}_{3}}-O-C{{H}_{2}}C{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}C{{H}_{2}}-O-C{{H}_{2}}C{{H}_{3}}\]
C) \[C{{H}_{3}}{{(C{{H}_{2}})}_{4}}-O-C{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{2}}-CH(C{{H}_{3}})-O-C{{H}_{2}}C{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}\xrightarrow[\text{Anti}\,\text{-}\,\text{Markownikoff }\!\!'\!\!\text{ s}\,\,\text{rule}]{\text{HBr/}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Br\] \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Br\xrightarrow[{{S}_{N}}2\,\,\text{reaction}]{{{C}_{2}}{{H}_{5}}ONa}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}O{{C}_{2}}{{H}_{5}}\]
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