A) \[\frac{{{\mu }_{0}}ne}{2\pi r}\]
B) zero
C) \[\frac{{{\mu }_{0}}{{n}^{2}}e}{r}\]
D) \[\frac{{{\mu }_{0}}ne}{2r}\]
Correct Answer: D
Solution :
As \[I=\frac{q}{t}\] So, for an electron revolving in a circular orbit of radius r q = e and t = T \[\Rightarrow \,\,\,\,\,I=\frac{e}{T}=\frac{e}{2\pi /\omega }=\frac{\omega e}{2\pi }=\frac{2\pi ne}{2\pi }=ne\] The magnetic field produced at the centre is \[B=\frac{{{\mu }_{0}}I}{2R}=\frac{{{\mu }_{0}}ne}{2r}\]You need to login to perform this action.
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