A) 80 cm
B) 100 cm
C) 120 cm
D) 140 cm
Correct Answer: C
Solution :
The fundamental frequencies of closed and open organ pipe are given as \[{{v}_{c}}=\frac{v}{4l}\] \[{{v}_{o}}=\frac{v}{2l'}\] Given the second overtone (i.e. third harmonic) of open pipe is equal to the fundamental frequency of closed pipe i.e. \[3{{v}_{o}}={{v}_{c}}\] \[\Rightarrow \,\,\,\,\,\,3\frac{v}{2l'}=\frac{v}{4l}\] \[\Rightarrow \,\,\,\,\,1'=6l=6\times 20=120cm\]You need to login to perform this action.
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