A) \[{{V}_{A}}={{V}_{B}}={{V}_{C}}\]
B) \[{{V}_{A}}\ne {{V}_{B}}={{V}_{C}}\]
C) \[{{V}_{A}}={{V}_{B}}\ne {{V}_{C}}\]
D) \[{{V}_{A}}\ne {{V}_{B}}\ne {{V}_{C}}\]
Correct Answer: A
Solution :
The equivalent resistance between Q and S is given by \[\frac{1}{R'}=\frac{1}{1.5R}+\frac{1}{3R}=\frac{2+1}{3R}\] \[\Rightarrow \,\,\,\,\,R'=R\] Now, \[{{V}_{PQ}}={{V}_{A}}+IR\] Also \[{{V}_{QS}}={{V}_{B}}={{V}_{C}}=IR\] Hence, \[{{V}_{A}}={{V}_{B}}={{V}_{C}}\]You need to login to perform this action.
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