A) \[CO_{3}^{2-},SO_{3}^{2-}\]
B) \[ClO_{3}^{-},\,CO_{3}^{2-}\]
C) \[SO_{3}^{2-},NO_{3}^{-}\]
D) \[ClO_{3}^{-},SO_{3}^{2-}\]
Correct Answer: D
Solution :
\[CIO_{3}^{-},=SO_{3}^{2-}\] Number of electrons \[CO_{3}^{2-}=6+2+24=32\] \[SO_{3}^{2-}=16+2+24=42\] \[CIO_{3}^{-}=17+24+1=42\] \[CO_{3}^{2-}=6+24+2=32\] \[NO_{3}^{2-}=7+2+24=33\] Hence, \[CIO_{3}^{-}\] and \[SO_{3}^{2-}\] are isoelectronic and are pyramidal in shape.You need to login to perform this action.
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