A) 1 : 4
B) 4 : 1
C) 16 : 1
D) 2 : 1
Correct Answer: B
Solution :
Let the mass of \[{{H}_{2}}\] gas be \[xg\] and mass of \[{{O}_{2}}\]gas 4xg Molar \[{{H}_{2}}:{{O}_{3}}\] Mass \[2:32\] i.e. \[1:16\] \[\therefore \] Molar ratio = \[\frac{{{n}_{{{H}_{2}}}}}{{{n}_{{{O}_{2}}}}}=\frac{x/2}{4x/32}=\frac{x\times 32}{2\times 4x}=\frac{4}{1}=4:1\]You need to login to perform this action.
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