A) 17. 36
B) 18.20
C) 16.76
D) 15.76
Correct Answer: C
Solution :
Experimental values \[{{P}_{{{N}_{2}}}}\,={{P}_{total}}\,-{{P}_{{{H}_{2}}O}}\,=725\,-25\,=700\,\text{mm}\] According to Duma's method for estimation of N, Weight of nitrogen \[=\frac{pVM}{RT}\] where, p is pressure = 700 mm V of nitrogen = 40mL M molecular mass of \[{{N}_{2}}=28\] \[R-0.0821\] \[T-300K=\frac{700\times 40\times 28}{760\times 1000\,\times 300\,\times 0.0821}=0.042g\] \[\therefore \] & of nitrogen \[=\frac{0.042}{0.25}\times 100=16.573%\]You need to login to perform this action.
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