NEET NEET SOLVED PAPER 2015 (C)

  • question_answer
    The enolic form of ethyl acetoacetate as below has                                                                        

    A)  18 sigma bonds and 2 pi-bonds

    B)  16 sigma bonds and 1 pi-bond

    C)  9 sigma bonds and 2 pi-bonds

    D)  9 sigma bonds and 1 pi-bond

    Correct Answer: A

    Solution :

                    The enolic form of ethyl acetoacetate has 16 single bonds i.e. 16 \[\sigma \]-bonds and 2 double bonds i.e. 2 \[\sigma \]-bonds and 2 \[\pi \]-bonds. Hence, the given structure has 18 \[\sigma \]-bonds and 2\[\pi \]-bonds.


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