A) 12.65
B) 2.0
C) 7.0
D) 1.04
Correct Answer: A
Solution :
Key concept When equal volumes of acid and base are mixed, then resulting solution become alkaline if concentration of base is taken high. Let normality of the solution after mixing 0.1 M \[NaOH\,\text{and}\,\text{0}\text{.01M}\,\text{HCl}\]is N. \[\therefore \] \[{{N}_{1}}{{V}_{1}}-{{N}_{2}}{{V}_{2}}=NV\] or \[0.1\times 1-0.01\times 1=N\times 2\] Since, normality of \[NaOH\] is more than that of \[HCl\]. Hence, the resulting solution is alkaline. or \[[\overset{\_}{\mathop{O}}\,H]=N=\frac{0.09}{2}=0.045N\] or \[pOH=-\log (0.045)=1.35\] \[\therefore \] \[pH=14-pOH\] \[=14-1.35=12.65\]You need to login to perform this action.
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