A) \[{{(C{{H}_{3}})}_{2}}CH-\underset{\underset{\text{C}{{\text{H}}_{\text{3}}}}{\mathop{|}}\,}{\mathop{CH}}\,-CH=C{{H}_{2}}\]
B) \[{{(C{{H}_{3}})}_{3}}C-CH=C{{H}_{2}}\]
C) \[{{(C{{H}_{3}})}_{2}}C=CH-C{{H}_{2}}-C{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{2}}CH-C{{H}_{2}}-CH=C{{H}_{2}}\]
Correct Answer: A
Solution :
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