A) \[C{{l}_{2}}{{O}_{7}}\] is an anhydride of perchloric acid
B) \[{{O}_{3}}\]molecule is bent
C) OFN is isoelectronic with \[N{{O}_{2}}\]
D) \[O{{F}_{2}}\]is an oxide of fluorine
Correct Answer: D
Solution :
(a) \[C{{l}_{2}}{{O}_{7}}\] is an anhydride of perchloric acid \[2HCl{{O}_{4}}\xrightarrow[-{{H}_{2}}O]{\Delta }C{{l}_{2}}{{O}_{7}}\] (b) Shape of \[{{O}_{3}}\] molecule is bent. (c) Number of electrons in ONF = 24 Number of electrons in \[N{{O}_{2}}\] = 24 \[\therefore \] ONF and \[N{{O}_{2}}\] both are isoelectronic. (d) \[O{{F}_{2}}\] is a fluoride of oxygen because electronegativity of fluorine is more than that of oxygen. \[O{{F}_{2}}\] = Oxygen difluorideYou need to login to perform this action.
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