A) \[-315\,kJ\]
B) \[+315\,kJ\]
C) \[-630\,kJ\]
D) \[-3.15kJ\]
Correct Answer: A
Solution :
Given, \[C(s)+{{O}_{2}}(g)\xrightarrow{\,}\,C{{O}_{2}}(g);\] \[{{\Delta }_{f}}H=-393.5\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\] \[\because \]Heat released on formation of 44 g or 1 mole \[C{{O}_{2}}=-395.5kJmo{{l}^{-1}}\] \[\because \]Heat released on formation of 35.2 g of \[C{{O}_{2}}\] \[=\frac{-393.5kJmo{{l}^{-1}}}{44g}\times 35.2g=-315kJmo{{l}^{-1}}\]You need to login to perform this action.
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