A) 0.015
B) 0.020
C) 0.025
D) 0.010
Correct Answer: B
Solution :
Given, the value of coefficient of volume expansion of glycerin is\[5\times {{10}^{-4}}{{K}^{-1}}\]. As, original density of glycerin, \[\rho ={{\rho }_{0}}(1+Y\Delta T)\] \[\Rightarrow \,\,\,\,\,\rho -{{\rho }_{0}}={{\rho }_{0}}Y\Delta T\] Thus, fractional change in the density of glycerine for a rise of \[{{40}^{\text{o}}}C\] in its temperature, \[\frac{\rho -{{\rho }_{0}}}{{{\rho }_{0}}}=Y\Delta T=5\times {{10}^{-4}}\times 40=200-\times {{10}^{-4}}=0.020\]
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