A) \[\frac{L}{l}+1\]
B) \[\frac{L}{l}-1\]
C) \[\frac{L+1}{L-1}\]
D) \[\frac{L}{l}\]
Correct Answer: D
Solution :
We know, magnification of telescope, we have \[M=\frac{{{f}_{o}}}{{{f}_{e}}},\] Here \[\frac{{{f}_{e}}}{{{f}_{e}}+u}=\frac{-I}{L}\] Þ \[\frac{{{f}_{e}}}{{{f}_{e}}-({{f}_{o}}+{{f}_{e}})}\,=\frac{-I}{L}\] Þ \[\frac{{{f}_{e}}}{{{f}_{o}}}=\frac{I}{L}i.e.M=\frac{L}{I}\]You need to login to perform this action.
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