A) 7.76 \[km{{s}^{-1}}\]
B) 8.5\[km{{s}^{-1}}\]
C) 9.13 \[km{{s}^{-1}}\]
D) 6.67 \[km{{s}^{-1}}\]
Correct Answer: A
Solution :
Given, height of a satellite \[h=0.25\times {{10}^{6}}m\] Earth's radius, \[{{R}_{e}}=6.38\times {{10}^{6}}m\] For the satellite revolving around the earth, orbital velocity of the satellite. \[{{v}_{0}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}\left[ 1+\frac{h}{{{R}_{e}}} \right]}}\]\[{{v}_{0}}\sqrt{\frac{g{{R}_{e}}}{1+\frac{h}{{{R}_{e}}}}}\] Substitutes the value of \[g,{{\operatorname{R}}_{e}}\] and h, we get \[{{v}_{0}}=\sqrt{60\times {{10}^{6}}}m/s\] \[{{v}_{0}}=7.76\times {{10}^{3}}m/s=7.76km/s\]You need to login to perform this action.
You will be redirected in
3 sec