A) 1.70
B) 2.35
C) 3.0
D) 1.50
Correct Answer: A
Solution :
Given, pressure =150 mm of Hg Pumping rate of heart of a man \[=\frac{dV}{dt}=\frac{5\times {{10}^{-3}}}{60}{{m}^{3}}/s\] Power of heart, = \[P.\frac{dV}{dt}=\rho gh.\frac{dV}{dt}[p=\rho gh]\] \[\Rightarrow \,\,\frac{(1.36\times {{10}^{3}}kg/{{m}^{3}})(10)\times 0.15\times 5\times {{10}^{-3}})}{60}=1.70W\]You need to login to perform this action.
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