A) \[\frac{L{{E}_{0}}f}{l\,{{r}_{1}}}\]
B) \[\frac{{{E}_{0}}r}{(r+{{r}_{1}})}.\frac{l}{L}\]
C) \[\frac{{{E}_{0}}l}{L}\]
D) \[\frac{L{{E}_{0}}r}{(r+{{r}_{1}})l}\]
Correct Answer: B
Solution :
Consider a potentiometer wire of length L and a resistance r are connected in series with a battery of e. m. f. \[{{E}_{0}}\] and a resistance \[{{r}_{1}}\] as shown in figure. Current in wire \[AB=\frac{{{E}_{0}}}{{{r}_{1}}+r}\]You need to login to perform this action.
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