question_answer

Number of possible isomers for the complex \[[Co{{(en)}_{2}}C{{l}_{2}}]Cl\] will be (en = ethylenediamine)       

A)                          2                            

B)  1                            

C)                         3                            

D)  4

Correct Answer: C

Solution :

\[[Co{{(en)}_{2}}C{{l}_{2}}]Cl\] Possible isomers are Hence, total number of Stereoisomers \[=2+1=3\]