A) \[x=\frac{{{m}_{1}}L}{{{m}_{1}}+{{m}_{2}}}\]
B) \[x=\frac{{{m}_{1}}}{{{m}_{2}}}L\]
C) \[x=\frac{{{m}_{2}}}{{{m}_{1}}}L\]
D) \[x=\frac{{{m}_{2}}L}{{{m}_{1}}+{{m}_{2}}}\]
Correct Answer: D
Solution :
As two point masses \[{{m}_{1}}\] and \[{{m}_{2}}\] are placed at opposite ends of a rigid rod of length L and negligible mass as shown in figure.You need to login to perform this action.
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