2. Solved Papers
  3. NEET

NEET NEET SOLVED PAPER 2015 (Re)

  • question_answer
    If the equilibrium constant for \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\] is K, the equilibrium constant for                    \[\frac{1}{2}{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)NO(g)\] will the

    A)  \[{{K}^{1/2}}\]                                 

    B)  \[\frac{1}{2}K\]               

    C)         K                           

    D)         \[{{K}_{2}}\]

    Correct Answer: A

    Solution :

    Plan As we can see the reaction for which we have to find out equilibrium constant is different only in stoichiometric coefficient as compared to the given reaction. Hence, we can find equilibrium constant for the required reaction with the help of mentioned equilibrium constant in the problem. Given, equilibrium constant for the reaction, \[{{N}_{2}}(g)+{{O}_{2}}(g)2NO(g)\]is K i.e. \[K=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}\]                                               ?(i) Let equilibrium constant for the reaction, \[\frac{1}{2}{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)NO(g)\]is \[K'\]i.e. \[\,K'\,=\frac{[NO]}{{{[{{N}_{2}}]}^{1/2}}\,{{[{{O}_{2}}]}^{1/2}}}\] On squaring both sides \[K{{'}^{2}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}\]                               ?(ii) On comparing Eqs. (i) and (ii), we get \[K=K{{'}^{2}}\] or            \[K'=\sqrt{K}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner