A) 2
B) 3
C) 4
D) 1
Correct Answer: A
Solution :
Given, that two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius \[\frac{r}{2}\] and lighter one in radius r as shown in figure. As, lighter stone is n times that of the value of heavier stone when they experience same centripetal forces, we get \[{{({{F}_{c}})}_{\text{heavier}}}={{({{F}_{c}})}_{\text{lighter}}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\frac{2m{{(v)}^{2}}}{(r/2)}=\frac{m{{(nv)}^{2}}}{r}\] \[\Rightarrow \,\,\,\,{{n}^{2}}=4\] \[\Rightarrow \,\,\,\,\,n=2\]You need to login to perform this action.
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