A) \[\frac{2\sqrt{2}}{3}v\]
B) \[\frac{3}{4}v\]
C) \[\frac{3}{\sqrt{2}}v\]
D) \[\frac{\sqrt{3}}{2}v\]
Correct Answer: A
Solution :
According to law of conservation of kinetic energy, we have \[\frac{1}{2}M{{v}^{2}}+0=\frac{1}{2}M{{\left( \frac{v}{3} \right)}^{2}}+\frac{1}{2}Mv_{2}^{2}\] Þ \[{{v}^{2}}=\frac{{{v}^{2}}}{9}+v_{2}^{2}\] Þ \[{{v}^{2}}-\frac{{{v}^{2}}}{9}=v_{2}^{2}\Rightarrow \frac{8{{v}^{2}}}{9}\] Velocity of second block after collision \[{{v}_{2}}=\frac{2\sqrt{2}}{3}v\]You need to login to perform this action.
You will be redirected in
3 sec