A) \[6.66\,kg\,{{m}^{2}}{{s}^{-2}}\]
B) \[8.58\,kg\,{{m}^{2}}{{s}^{-2}}\]
C) \[10.86\,kg\,{{m}^{2}}{{s}^{-2}}\]
D) \[2.86\,kg\,{{m}^{2}}{{s}^{-2}}\]
Correct Answer: A
Solution :
As velocity of an automobile vehicle, \[v=54km/hr=54\times \frac{5}{18}=15m/s\] Angular velocity of a vehicle, \[v={{\omega }_{0}}r\] \[\Rightarrow \,\,\,\,\,{{\omega }_{0}}=\frac{v}{R}=\frac{15}{0.45}=\frac{100}{3}rad/s\] So, angular acceleration of an automobile, \[\alpha =\frac{\Delta \omega }{t}=\frac{{{\omega }_{t}}-{{\omega }_{0}}}{t}=\frac{0-\frac{100}{3}}{15}=\frac{-100}{45}rad/{{s}^{2}}\] Thus, average torque transmitted by its brakes to wheel \[\tau =I\alpha \] \[\Rightarrow \,\,\,\,\,3\times \frac{100}{45}=6.66kg{{m}^{2}}{{s}^{-2}}\] Physics for medical Entrance (Digvijay Singh) we needed for attempting medium difficult questions. When mica is introduced, capacitance will increase hence voltage across capacitor, get decrease.You need to login to perform this action.
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