A) 2.365 W
B) 23.65 W
C) 236.5 W
D) 2365 W
Correct Answer: C
Solution :
\[\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\](Where \[{{Q}_{2}}\] is heat removed) \[\Rightarrow \] \[\frac{600\times 4.2}{W}=\frac{277}{303-277}\] \[\Rightarrow \] \[W=236.5\,\text{joule}\] \[\Rightarrow \] \[Power\,\,=\,\,\frac{W}{t}=\frac{236.5\,joule}{1\,\sec }=236.5\,\,watt.\]You need to login to perform this action.
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