A) Disk
B) Sphere
C) Both reach at the same time
D) Depends on their masses
Correct Answer: B
Solution :
\[a=\frac{g\sin \theta }{1+\frac{{{K}^{2}}}{{{R}^{2}}}}\] for disc ; \[\frac{{{K}^{2}}}{{{R}^{2}}}=\frac{1}{2}=0.5\] for sphere ; \[\frac{{{K}^{2}}}{{{R}^{2}}}=\frac{2}{5}=0.4\] (sphere) > a(disc) \[\therefore \] sphere reaches firstYou need to login to perform this action.
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