A) \[0.025\text{ }\times \text{ }{{10}^{4}}\text{ }{{m}^{1}}\]
B) \[0.5\text{ }\times \text{ }{{10}^{7}}\text{ }{{m}^{1}}\]
C) \[0.25\text{ }\times \text{ }{{10}^{7}}\text{ }{{m}^{1}}\]
D) \[2.5\text{ }\times \text{ }{{10}^{7}}\text{ }{{m}^{1}}\]
Correct Answer: C
Solution :
\[\frac{1}{\lambda }=R{{Z}^{2}}\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)={{10}^{7}}\times {{1}^{2}}\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{\infty }^{2}}} \right)\]\[\Rightarrow \]wave number \[=\frac{1}{\lambda }=0.25\times {{10}^{7}}{{\text{m}}^{-1}}\]You need to login to perform this action.
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