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NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    The temperature inside a refrigerator is \[{{t}_{2}}^{{}^\circ }C\] and the room temperature is \[{{t}_{2}}^{{}^\circ }C.\]The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

    A)  \[\frac{{{t}_{1}}}{{{t}_{1}}-{{t}_{2}}}\]                   

    B)  \[\frac{{{t}_{1}}+273}{{{r}_{1}}-{{t}_{1}}}\]

    C)   \[\frac{{{t}_{2}}+273}{{{t}_{1}}-{{t}_{2}}}\]                      

    D)  \[\frac{{{t}_{1}}+{{t}_{2}}}{{{t}_{1}}+273}\]

    Correct Answer: B

    Solution :

                \[K=\frac{{{Q}_{2}}}{W}=\frac{1}{\frac{{{t}_{1}}}{{{t}_{2}}}-1}\]             \[{{Q}_{2}}=\frac{{{t}_{2}}W}{{{t}_{1}}-{{t}_{2}}}\]             \[{{Q}_{1}}={{Q}_{2}}+W=\frac{{{t}_{2}}W}{{{t}_{1}}-{{t}_{2}}}+W\] \[\frac{{{t}_{1}}W}{{{t}_{1}}-{{t}_{2}}}=\frac{{{t}_{1}}+273}{{{t}_{1}}-{{t}_{2}}}\]


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