A) \[{{\lambda }_{0}}=\frac{2mc{{\lambda }^{2}}}{h}\]
B) \[{{\lambda }_{0}}=\frac{2h}{mc}\]
C) \[{{\lambda }_{0}}=\frac{2{{m}^{2}}{{c}^{2}}{{\lambda }^{2}}}{{{h}^{2}}}\]
D) \[{{\lambda }_{0}}=\lambda \]
Correct Answer: A
Solution :
Momentum \[P=\frac{h}{\lambda }\Rightarrow E=\frac{{{P}^{2}}}{2m}\Rightarrow \frac{{{h}^{2}}}{2m{{\lambda }^{2}}}=\frac{hc}{{{\lambda }_{0}}}\] \[P=\frac{h}{\lambda }\Rightarrow {{\lambda }_{0}}=\frac{hc}{{{h}^{2}}}2m{{\lambda }^{2}}\] \[=\frac{2mc{{\lambda }^{2}}}{h}\]
You need to login to perform this action.
You will be redirected in
3 sec
