A) \[\frac{16}{25}\lambda \]
B) \[\frac{9}{16}\lambda \]
C) \[\frac{20}{7}\lambda \]
D) \[\frac{20}{13}\lambda \]
Correct Answer: C
Solution :
\[\lambda =\frac{1}{R\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)}\] \[{{\lambda }^{\grave{\ }}}=\frac{1}{R\left( \frac{1}{{{3}^{2}}}-\frac{1}{{{4}^{2}}} \right)}\] \[\frac{{{\lambda }^{\grave{\ }}}}{\lambda }=\frac{\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{3}^{2}}} \right)}{\left( \frac{1}{{{3}^{2}}}-\frac{1}{{{4}^{2}}} \right)}\Rightarrow {{\lambda }^{\grave{\ }}}=\frac{20\lambda }{7}\]
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