A) 10 mV
B) 20 mV
C) 30 mV
D) 15 mV
Correct Answer: B
Solution :
\[{{R}_{C}}=2K\Omega {{V}_{0}}=4V\] \[{{I}_{C}}=\frac{4V}{{{R}_{C}}}=\frac{4V}{2k}=2mA\] \[\beta =\frac{{{I}_{C}}}{{{I}_{B}}}=100\] \[\Rightarrow {{I}_{g}}=\frac{{{I}_{C}}}{100}=2\times {{10}^{-5}}A\] \[{{V}_{in}}{{I}_{B}}{{R}_{i}}=2\times {{10}^{-5}}\times 1K\Omega =20mV\]
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