A) \[\frac{a-f}{1+b}\]
B) \[\frac{a+f}{2(b-1)}\]
C) \[\frac{a+f}{2(1+b)}\]
D) \[\frac{f-a}{2(1+b)}\]
Correct Answer: D
Solution :
\[{{V}_{p}}=\frac{d{{x}_{p}}}{dt}=a+2bt\] \[{{V}_{Q}}=\frac{d{{x}_{Q}}}{dt}=f-2t\] \[{{V}_{p}}={{V}_{Q}}\] \[\Rightarrow a+2bt=f-2t\] \[2t+2bt=f-a\] \[\Rightarrow t=\frac{f-a}{2(b+1)}\]You need to login to perform this action.
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