A) \[{{L}_{A}}=\frac{{{L}_{B}}}{2}\]
B) \[{{L}_{A}}=2{{L}_{B}}\]
C) \[{{L}_{g}}>{{L}_{A}}\]
D) \[{{L}_{A}}>{{L}_{g}}\]
Correct Answer: C
Solution :
\[E=\frac{{{L}^{2}}}{21}\] \[\Rightarrow {{E}_{A}}={{E}_{B}}\] \[\Rightarrow \frac{{{L}^{2}}_{A}}{2{{I}_{A}}}=\frac{{{L}^{2}}_{B}}{2{{I}_{B}}}\] \[{{I}_{g}}>{{I}_{A}}\Rightarrow {{L}_{g}}>{{L}_{A}}\]You need to login to perform this action.
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