A) \[K={{K}_{1}}+{{K}_{2}}+{{K}_{3}}+3{{K}_{4}}\]
B) \[K=\frac{2}{3}({{K}_{1}}+{{K}_{2}}+{{K}_{3}})+2{{K}_{4}}\]
C) \[\frac{2}{K}=\frac{3}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}}+\frac{1}{{{K}_{4}}}\]
D) \[\frac{1}{K}=\frac{1}{{{K}_{1}}}+\frac{1}{{{K}_{2}}}+\frac{1}{{{K}_{3}}}+\frac{3}{2{{K}_{4}}}\]
Correct Answer: C
Solution :
\[{{K}_{1}},{{K}_{2}}\,and\,{{K}_{3}}\]are in parallel so Arithmetic mean. \[{{K}_{eq}}=\frac{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}}{3}\] \[{{K}_{eq}}\] is an series with\[K{{ & }_{4}}\]. So harmonic mean. \[\Rightarrow \frac{2}{k}=\frac{1}{{{K}_{eq}}}+\frac{1}{{{K}_{4}}}\] \[\Rightarrow \frac{2}{k}=\frac{3}{{{K}_{1}}+{{K}_{2}}+{{K}_{3}}}+\frac{1}{{{K}_{4}}}\]You need to login to perform this action.
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