NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    A bullet of mass 10 g moving horizontally with a velocity of\[400m{{s}^{-1}}\]strikes a wood block of mass 2 kg which is suspended by light inextensible string of length 5 m. As a result, the centre of gravity of the block found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

    A)  \[100m{{s}^{-1}}\]                

    B)  \[80m{{s}^{-1}}\]

    C)  \[120m{{s}^{-1}}\]                

    D)  \[160m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

    Apply conservation of linear momentum. CM rises through height h, so its velocity after collision\[=\sqrt{2gh}\] \[0.01\times 400=2\times \sqrt{2gh}+0.01\times v\] ⇒ \[V=120m/s\]


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