A) \[C{{u}^{+}}2{{H}_{2}}S{{O}_{4}}\to CuS{{O}_{4}}+S{{O}_{2}}+2{{H}_{2}}O\]
B) \[3S+2{{H}_{2}}S{{O}_{4}}\to 3S{{O}_{2}}+2{{H}_{2}}O\]
C) \[C+2{{H}_{2}}S{{O}_{4}}\to C{{O}_{2}}+2S{{O}_{2}}+2{{H}_{2}}O\]
D) \[C{{a}_{2}}+{{H}_{2}}S{{O}_{4}}\to CaS{{O}_{4}}+2HF\]
Correct Answer: D
Solution :
\[Ca{{F}_{2}}+{{H}_{2}}S{{O}_{4}}\to CaS{{O}_{4}}+2HF\] In this reaction there is no change in oxidation state of any atom.
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