NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    Two rotating bodies A and B of masses m and 2m with moments of inertia\[{{I}_{A}}\,and\,{{I}_{g}}({{I}_{g}}>{{I}_{A}})\]have equal kinetic energy of rotation. If \[{{L}_{A}}and\text{ }{{L}_{B}}\]be their angular momenta respectively, then

    A)  \[{{L}_{A}}=\frac{{{L}_{B}}}{2}\]               

    B)  \[{{L}_{A}}=2{{L}_{B}}\]

    C)  \[{{L}_{g}}>{{L}_{A}}\]                   

    D)  \[{{L}_{A}}>{{L}_{g}}\]

    Correct Answer: C

    Solution :

                \[E=\frac{{{L}^{2}}}{21}\]             \[\Rightarrow {{E}_{A}}={{E}_{B}}\]             \[\Rightarrow \frac{{{L}^{2}}_{A}}{2{{I}_{A}}}=\frac{{{L}^{2}}_{B}}{2{{I}_{B}}}\]             \[{{I}_{g}}>{{I}_{A}}\Rightarrow {{L}_{g}}>{{L}_{A}}\]


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