A) \[{{10}^{-47}}C\]
B) \[{{10}^{-20}}C\]
C) \[{{10}^{-23}}C\]
D) \[{{10}^{-37}}C\]
Correct Answer: D
Solution :
\[{{F}_{e}}={{F}_{g}}\] \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{\Delta {{e}^{2}}}{{{d}^{2}}}=\frac{G{{m}^{2}}}{{{d}^{2}}}\] \[9\times {{10}^{9}}(\Delta {{e}^{2}})=6.67\times {{10}^{-11}}\times 1.67\] \[\times {{10}^{-27}}\times 1.67\times {{10}^{-27}}\] \[\Delta {{e}^{2}}=\frac{6.67\times 1.67\times 1.67}{9}\times {{10}^{-74}}\] \[\Delta \Epsilon \approx {{10}^{-37}}\]You need to login to perform this action.
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