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NEET NEET SOLVED PAPER 2017

  • question_answer
    A long solenoid of diameter 0.1 m has\[2\times {{10}^{4}}\] turns per meter. At the centre of the solenoid, a coil of 100 turns and radius 0.01 m is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to 0 A from 4 A in 0.05 s. If the resistance of the coil is\[10{{\pi }^{2}}\Omega ,\] the total charge flowing through the coil during this time is                                                                                                            

    A)  \[16\pi \,\mu C\]                            

    B) \[32\pi \,\mu C\]

    C)   \[16\mu C\]                     

    D)  \[32\,\mu C\]

    Correct Answer: D

    Solution :

                     \[\varepsilon =-N\frac{d\text{o }\!\!|\!\!\text{ }}{dt}\]                               \[\left| \frac{\varepsilon }{R} \right|=\frac{N}{R}\frac{d\text{o }\!\!|\!\!\text{ }}{dt}\]                                \[dq=\frac{N}{R}d\text{o }\!\!|\!\!\text{ }\]                                 \[\Delta Q=\frac{N(\Delta \text{o }\!\!|\!\!\text{ })}{R}\]                                 \[\Delta Q=\frac{\Delta \text{o}{{\text{ }\!\!|\!\!\text{ }}_{\text{total}}}}{R}\]                                 \[=\frac{(NBA)}{R}\]                                 \[=\frac{{{\mu }_{0}}ni\pi {{r}^{2}}}{R}\] Putting values \[=\frac{4\pi \times {{10}^{-7}}\times 100\times 4\times \pi \times {{(0.01)}^{2}}}{10{{\pi }^{2}}}\] \[\Delta Q=32\,\mu C\]


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