A) \[-8\,m/{{s}^{2}}\]
B) 0
C) \[5\,m/{{s}^{2}}\]
D) \[-4\,m/{{s}^{2}}\]
Correct Answer: D
Solution :
\[x=5t-2{{t}^{2}}\] \[y=10t\] \[\frac{dx}{dt}=5-4t\] \[\frac{dy}{dt}=10\] \[{{v}_{x}}=5-4t\] \[{{v}_{y}}=10\] \[\frac{dv}{dt}x=-4\] \[\frac{dv}{dt}y=10\] \[{{a}_{x}}=-4\] \[{{a}_{y}}=0\] Acceleration of particle at t = 2 s is\[~=4\text{ }m/{{s}^{2}}\]You need to login to perform this action.
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