A) Gabriels phthalimide synthesis
B) Carbylamine reaction
C) Hoffmann hypobromamide reaction
D) Stephens reaction
Correct Answer: C
Solution :
\[C{{H}_{3}}-\overset{\text{O}}{\mathop{\overset{||}{\mathop{C}}\,}}\,-N{{H}_{2}}+B{{r}_{2}}+4NaOH\xrightarrow{\Delta }\]\[C{{H}_{3}}-N{{H}_{2}}+2NaBr+N{{a}_{2}}C{{O}_{3}}+3{{H}_{2}}O\] This is Hoffmann Bromamide reaction.
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